Function trimEndDotSlashes

trim all trivial trailing forward-slashes ("/") and dot-slashes ("./"), at the end a string. but exclude non-trivial dotdotslash ("/../") from being wrongfully trimmed.

TODO: this operation is somewhat expensive, because:
the implementation uses regex, however it was not possible for me to design a regex that handles the input string as is, so I resort to reversing the input string, and using a slightly easier-to-design regex that discovers trivial (dot)slashes in reverse order, and then after the string replacement, I reverse it again and return it as the output.

Example

import { assertEquals } from "jsr:@std/assert"

// aliasing our functions for brevity
const eq = assertEquals, fn = trimEndDotSlashes

eq(fn("a/b.zip/c.txt"),                "a/b.zip/c.txt")
eq(fn("//a/b.zip//"),                  "//a/b.zip")
eq(fn("/"),                            "")
eq(fn("./"),                           "")
eq(fn("//././//./"),                   "")
eq(fn(".//././//./"),                  "")
eq(fn(".//./..///./"),                 ".//./../")
eq(fn("/a/b.zip/./"),                  "/a/b.zip")
eq(fn("/a/b.zip/../"),                 "/a/b.zip/../")
eq(fn("/a/b.zip/..//"),                "/a/b.zip/../")
eq(fn("/a/b.zip/.././"),               "/a/b.zip/../")
eq(fn("a/b.zip///././///.////"),       "a/b.zip")
eq(fn("/a/b.zip///././///.////"),      "/a/b.zip")
eq(fn("/a/b.zip/.././/.././///.////"), "/a/b.zip/.././/../")
eq(fn("/a/b.zip/././././///.////"),    "/a/b.zip")
eq(fn("/a/b.zip./././././///.////"),   "/a/b.zip.")
eq(fn("/a/b.zip../././././///.////"),  "/a/b.zip..")
eq(fn("/a/b.zip.../././././///.////"), "/a/b.zip...")
eq(fn("file:///a/b.zip//c.txt"),       "file:///a/b.zip//c.txt")

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